Two capacitors having capacitance |CAPACITANCEJEEMAIN2023

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JEE MAIN 2022

26-06-2022 S1

Question

Two capacitors having capacitance $\mathrm{C}_1$ and $\mathrm{C}_2$ respectively are connected as shown in figure. Initially, capacitor C1 is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor $\mathrm{C}_1$ is now connected to uncharged capacitor $\mathrm{C}_2$ by closing the switch S. The amount of charge on the capacitor $\mathrm{C}_2$, after equilibrium is :

Select the correct option:

A

$\frac{C_1 C_2}{\left(C_1+C_2\right)} V$

B

$\frac{\left(C_1+C_2\right)}{C_1 C_2} V$

C

$\left(C_1+C_2\right) V$

D

$\left(C_1-C_2\right) V$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Charge on capacitor $\mathrm{C}_2$ $$ =\frac{C_2 \times Q_{\text {total }}}{C_{\text {total }}}=\frac{C_2\left[C_1 V\right]}{C_1+C_2}=\frac{C_1 C_2 V}{C_1+C_2} $$

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