Wheatstone bridge principle is used to measu... | Current Electricity

JEE MAIN 2024

27-01-24 S2

Question

Wheatstone bridge principle is used to measure the specific resistance $\left(S_1\right)$ of given wire, having length L , radius r . If X is the resistance of wire, then specific resistance is: $\mathrm{S}_1=\mathrm{X}\left(\frac{\pi \mathrm{r}^2}{\mathrm{~L}}\right)$. If the length of the wire gets doubled then the value of specific resistance will be

Select the correct option:

$\frac{S_1}{4}$

$2 \mathrm{~S}_1$

$\frac{S_1}{2}$

$S_1$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

As specific resistance does not depends on dimension of wire so, it will not change.

Question Tags

JEE Main

Physics