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JEE Advance 2009
Paper-1
Question
When a particle is restricted to move along x -axis between $\mathrm{x}=0$ and $\mathrm{x}=\mathrm{a}$, where a is of nanometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends $x=0$ and $x=a$. The wavelength of this standing wave is related to the linear momentum p of the particle according to the de Broglie relation. The energy of the particle of mass $m$ is related to its linear momentum as $E=p^2 / 2 m$. Thus, the energy of the particle can be denoted by a quantum number ' $n$ ' taking values $1,2,3, \ldots$. ( $n=1$, called the ground state) corresponding to the number of loops in the standing wave.

Use the model described above to answer the following three questions for a particle moving in the line $\mathrm{x}=0$ to $\mathrm{x}=\mathrm{a}$. Take $\mathrm{h}=6.6 \times 10^{-34} \mathrm{Js}$ and $\mathrm{e}=1.6 \times 10^{-19} \mathrm{C}$.

The speed of the particle that can take discrete values is proportional to
Select the correct option:
A
$\mathrm{n}^{-3 / 2}$
B
$\mathrm{n}^{-1}$
C
$n^{1 / 2}$
D
$n$
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