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JEE Main 2023
29-01-2023_S2
Question
Let $\alpha=8-14 i, \quad A=\left\{z \in C: \frac{\alpha z-\bar{\alpha} \bar{z}}{z^2-(\bar{z})^2-112 i}=1\right\}$ and $B=\{z \in C:|z+3 i|=4\}$ Then $\sum_{\varepsilon \in A \subset B}($ Rez - Imz $)$ is equal to $\_\_\_\_$ .
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