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JEE-Main_2024
JEE-Main_30.01.24_(S1)
Question
A spherical body of mass 100" " g is dropped from a height of 10" " m from the ground. After hitting the ground, the body rebounds to a height of 5" " m. The impulse of force imparted by the ground to the body is given by : $\left(\right.$ given $\left.\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\right)$
Select the correct option:
A
$4.32 \mathrm{~kg} \mathrm{~ms}^{-1}$
B
$23.9 \mathrm{~kg} \mathrm{~ms}^{-1}$
C
$43.2 \mathrm{~kg} \mathrm{~ms}^{-1}$
D
$2.39 \mathrm{~kg} \mathrm{~ms}^{-1}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \vec{I}=\Delta \vec{P}=\vec{P}_f-\vec{P}_i \\ & \mathrm{M}=0.1 \mathrm{~kg} \\ & I=\Delta P=0.1(\sqrt{2 \times 9.8 \times 5}-(-\sqrt{2 \times 9.8 \times 10})) \\ & =0.1(14+7 \sqrt{2}) \approx 2.39 \mathrm{~kg} \mathrm{~ms}^{-1}\end{aligned}$
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