Vector & 3D_JEE-Main 06.04.24_(S1) - Competishun – Live JEE & NEET Courses and Exam Prep

JEE-Main 2024

06.04.24_(S1)

Question

The shortest distance between the lines $\frac{x-3}{2}=\frac{y+15}{-7}=\frac{z-9}{5}$ and $\frac{x+1}{2}=\frac{y-1}{1}=\frac{z-9}{-3}$ is $\_\_\_\_$

Select the correct option:

A

6√3

B

4√3

C

5√3

D

8√3

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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