If gcd(m, n) = 1 and 1² − 2².... | JEE Main 2023 | Sequences

JEE MAIN 2023

08-04-2023 S2

Question

If $\operatorname{gcd}(m, n)=1$ and $1^2-2^2+3^2-4^2+\ldots \ldots+(2021)^2-(2022)^2+(2023)^2=1012 m^2 n$, then $m^2-n^2$ is equal to

Select the correct option:

A

200

B

240

C

220

D

180

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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