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JEE MAIN 2024
31.01.24 S2
Question
The output of the given circuit diagram is
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Solution
$\begin{aligned} & \text { If } A=0 ; \bar{A}=1 \\ & A=1 ; \bar{A}=0 \\ & B=0 ; \bar{B}=1 \\ & B=1 ; \bar{B}=0 \\ & Y=\overline{(A+\bar{B})+(\bar{A}+B)}=\overline{(1+1)}=0\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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