An electromagnetic wave of frequency 3 GHz enters a dielectric medium of relative electric permittivity 2.25 from vacuum. The wavelength of this wave in that medium will be $\_\_\_\_$ $\times 10^{-2} \mathrm{~cm}$.
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Solution
λ in vacuum = c / f = (3 × 10⁸) / (3 × 10⁹) = 0.1 m
∴ λ in medium = 0.1 / μ
Where refractive index
μ = √(μᵣ εᵣ)
Assuming non-magnetic material μᵣ = 1
∴ μ = √2.25 = 1.5
λₘ = 0.1 / 1.5 = 1/15 m = 6.67 cm
= 667 × 10⁻² cm
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