A force F = (5y + 20) j N acts... | Work and Energy JEE Main

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JEE MAIN 2021

25-07-21 S2

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A force of $\mathrm{F}=(5 \mathrm{y}+20) \mathrm{j} \mathrm{N}$ acts on a particle. The workdone by this force when the particle is moved from $\mathrm{y}=0 \mathrm{~m}$ to $\mathrm{y}=10 \mathrm{~m}$ is....

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