The magnetic field vector of an electromagnetic wave is given by $B=B \circ \frac{i+j}{\sqrt{2}} \cos (k z-\omega t)$; where ${ }^{\hat{i}, \hat{j}}$ represents unit vector along $x$ and $y$-axis respectively. At $t=0 s$, two electric charges $q_1$ of $4 \pi$ coulomb and $q_2$ of $2 \pi$ coulomb located at $\left(0,0, \frac{\pi}{k}\right)$ and $\left(0,0, \frac{3 \pi}{k}\right)$, respectively. Have the same velocity of $0.5 c \hat{i}$, (where $c$ is the velocity of light). The ratio of the force acting on charge $\mathrm{q}_1$ to $\mathrm{q}_2$ is :-
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇