Let $\binom{n}{k}$ denotes ${ }^n C_k$ and $\left[\begin{array}{l}n \\ k\end{array}\right]=\left\{\begin{array}{cc}\binom{n}{k}, & \text { if } 0 \leq k \leq n \\ 0, & \text { otherwise }\end{array}\right.$
If $A_k=\sum_{i=0}^9\binom{9}{i}\left[\begin{array}{c}12 \\ 12-k+i\end{array}\right]+\sum_{i=0}^8\binom{8}{i}\left[\begin{array}{c}13 \\ { }^{13} C_{13}-k+i\end{array}\right]$ and $A_4-A_3=190 p$, then $p$ is equal to :
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