If ∑ from r=0 to 25 {⁵⁰Cᵣ · ⁵⁰⁻ʳC₂₅⁻ʳ} = K(⁵⁰C₂₅)... | Binomial Theorem

JEE MAIN 2019

10-01-2019 S2

Question

If $\sum_{\mathrm{r}=0}^{25}\left\{{ }^{50} \mathrm{C}_{\mathrm{r}} \cdot{ }^{50-\mathrm{r}} \mathrm{C}_{25-\mathrm{r}}\right\}=\mathrm{K}\left({ }^{50} \mathrm{C}_{25}\right)$, then K is equal to:

Select the correct option:

$2^{25}-1$

$(25)^2$

$2^{25}$

$2^{24}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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