A small bar magnet placed with its axis at 30°... | Magnetic Effects of Current

JEE MAIN 2020

04-09-2020 S1

Question

A small bar magnet placed with its axis at 30° with an external field of 0.06 T experiences a torque of 0.018 Nm. The minimum work required to rotate it from its stable to unstable equilibrium position is

Select the correct option:

$9.2 \times 10^{-3} \mathrm{~J}$

$6.4 \times 10^{-2} \mathrm{~J}$

$7.2 \times 10^{-2} \mathrm{~J}$

$11.7 \times 10^{-3} \mathrm{~J}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Medium

Start Preparing for JEE with Competishun

Report Issue