SE_JEE-Main 09-01-2020-S-2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2020

09-01-2020 S2

Question

If $A=\{x \in R:|x|<2\}$ and $B=\{x \in R:|x-2| \geq 3\}$; then

Select the correct option:

$\mathrm{A}-\mathrm{B}=[-1,2]$

$\mathrm{A} \cup \mathrm{B}=\mathrm{R}-(2,5)$

$\mathrm{B}-\mathrm{A}=\mathrm{R}-(-2,5)$

$\mathrm{A} \cap \mathrm{B}=(-2,-1)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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