The area (in sq. units)|Relations and Functions| JEEMAIN2020

JEE MAIN 2020

05-09-20 S2

Question

The area (in sq. units) of the region $A=\{(x, y): \quad(x-1)[x] \leq y \leq 2 \sqrt{x}, 0 \leq x \leq 2\}$, where $[t]$ denotes the greatest integer function, is :

Select the correct option:

$\frac{8}{3} \sqrt{2}-1$

$\frac{4}{3} \sqrt{2}+1$

$\frac{8}{3} \sqrt{2}-\frac{1}{2}$

$\frac{4}{3} \sqrt{2}-\frac{1}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Hard

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