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JEE Main 2020
02-09-2020 S1
Question
Let $y=y(x)$ be the solution of the differential equation, $\frac{2+\sin x}{y+1} \cdot \frac{d y}{d x}-\cos x, y>0, y(0)=1$. If $y(\pi) =a$ and $\frac{d y}{d x}$ at $x=\pi$ is $b$, then the ordered pair ( $a$, b) is equal to :
Select the correct option:
A
(2, 1)
B
(1, –1)
C
$\left(2, \frac{3}{2}\right)$
D
(1, 1)
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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