QE_JEE-MAIN 2019_(S1) - Competishun – Live JEE & NEET Courses and Exam Prep

JEE-MAIN 2019

12-01-2019 S1

Question

If $\lambda$ be the ratio of the roots of the quadratic equation in $x, 3 m^2 x^2+m(m-4) x+2=0$, then the least value of $m$ for which $\lambda+\frac{1}{\lambda}=1$, is

Select the correct option:

(1) $4-2 \sqrt{3} \mid$

$4-3 \sqrt{2}$

$2-\sqrt{3}$

$-2+\sqrt{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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