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JEE ADVANCE 2019
paper 1
Multiple correct answers - Select all that apply
Question
Let $\Gamma$ denote a curve $y=y(x)$ which is in the first quadrant and let the point $(1,0)$ lie on it. Let the tangent to $\Gamma$ at a point $P$ intersect the $y$-axis at $Y_{P^2}$. If $P Y_P$ has length 1 for each point $P$ on $\Gamma$, then which of the following options is/are correct?
Select ALL correct options:
A
$y=\log _e\left(\frac{1+\sqrt{1-x^2}}{x}\right)-\sqrt{1-x^2}$
B
$x y^{\prime}-\sqrt{1-x^2}=0$
C
$y=-\log _e\left(\frac{1+\sqrt{1-x^2}}{x}\right)+\sqrt{1-x^2}$
D
$x y^{\prime}+\sqrt{1-x^2}=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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JEE Advance
Mathematics
Easy
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