PHYSICS_JEE-ADVANCED-2014_P1 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE-ADVANCED-2014

PAPER 1

Multiple correct answers - Select all that apply

Question

One end of a taut string of length 3m along the x-axis is fixed at x = 0. The speed of the waves in the string is 100m/s. The other end of the string is vibrating in the y-direction so that stationary waves are set up in the string. The possible waveform(s) of these stationary waves is (are)

Select ALL correct options:

$y(t)=A \sin \frac{\pi x}{6} \cos \frac{50 \pi t}{3}$

$y(t)=A \sin \frac{\pi x}{3} \cos \frac{100 \pi t}{3}$

$y(t)=A \sin \frac{5 \pi x}{6} \cos \frac{250 \pi t}{3}$

$y(t)=A \sin \frac{5 \pi x}{2} \cos 250 \pi t$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

⚠ Partially correct. Some answers are missing.

Solution