The value of $\int_0^1\left(2 x^3-3 x^2-x+1\right)^{\frac{1}{3}} d x$ is equal to:
Select the correct option:
A
0.0
B
1
C
2
D
-1
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$
I=\int_0^1\left(2 x^3-3 x^2-x+1\right)^{\frac{1}{3}} d x
$$
Using $\int_0^{2 a} f(x) d x$ where $f(2 a-x)=-f(x)$
Here $f(1-x)=f(x)$
$$
\therefore \mathrm{I}=0
$$
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