Let $\int_0^x \sqrt{1-\left(y^{\prime}(t)\right)^2} \mathrm{dt}=\int_0^{\mathrm{x}} \mathrm{y}(\mathrm{t}) \mathrm{dt}, 0 \leq \mathrm{x} \leq 3, \mathrm{y} \geq 0, y(0)=0$. Then at $x=2, y^{\prime \prime}+y+1$ is equal to :
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