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JEE MAIN_2026
04-04-26_S2
Question
Two 4 bits binary numbers, $\mathrm{A}=1101$ and $\mathrm{B}=1010$ are given in the inputs of a logic circuit shown in figure below. The output $(\mathrm{Y})$ will be :
Select the correct option:
A
Y = 1101
B
Y = 0010
C
Y = 0111
D
Y = 1000
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
\begin{aligned} & \mathrm{Y}=\overline{\overline{\mathrm{A}} \cdot \mathrm{~B}}=\mathrm{A}+\overline{\mathrm{B}} \\ & \mathrm{~A}=1101 \\ & \mathrm{~B}=1010 \\ & \overline{\mathrm{~B}}=0101 \\ & \mathrm{~A}+\overline{\mathrm{B}}=1101 \end{aligned}
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