A displacement current| ELECTROMAGNETIC WAVE | JEE MAIN_2026

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JEE MAIN_2026

05-04-26_S1

Question

A displacement current of 4.0 A can be set up in the space between two parallel plates of $6 \mu \mathrm{~F}$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\alpha \times 10^6$ V/s. The value of $\alpha$ is $\_\_\_\_$ .

Select the correct option:

A

0.58

B

0.67

C

0.82

D

0.75

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & I_d=C \frac{d V}{d t} \\ & 4=\left(6 \times 10^{-6}\right)\left(\alpha \times 10^6\right) \\ & \alpha=\frac{2}{3} \approx 0.67\end{aligned}$

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