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JEE MAIN 2020
09-01-2020 S2
Question
A rod of length $L$ has non-uniform linear mass density given by $$ \rho(\mathrm{x})=\mathrm{a}+\mathrm{b}\left(\frac{\mathrm{x}}{\mathrm{~L}}\right)^2 $$ , where a and b are constants and $0 \leq x \leq L$. The value of $x$ for the centre of mass of the rod is at
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