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JEE MAIN 2022
28-07-2022 S2
Question
A slab of dielectric constant $K$ has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\frac{3}{4} d$, where $d$ is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
Select the correct option:
A
(A) $\frac{4 \mathrm{KC}_0}{3+\mathrm{K}}$
B
$\frac{3 \mathrm{KC}_0}{3+\mathrm{K}}$
C
$\frac{3+\mathrm{K}}{4 \mathrm{KC}_0}$
D
$\frac{\mathrm{K}}{4+\mathrm{K}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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