Consider the following reactions
$$
\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{O}_{4}}[\mathrm{~B}]+\mathrm{K}_{2} \mathrm{SO}_{4}
$$
The products $[\mathrm{A}]$ and $[\mathrm{B}]$, respectively are :
Select the correct option:
A
$\mathrm{K}_{2} \mathrm{Cr}(\mathrm{OH})_{6}$ and $\mathrm{Cr}_{2} \mathrm{O}_{3}$
B
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and CrO
C
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and $\mathrm{Cr}_{2} \mathrm{O}_{3}$
D
$\mathrm{K}_{2} \mathrm{CrO}_{4}$ and $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$
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