Consider the following reactions
$$
\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_{2} \mathrm{O}]{\mathrm{H}_{2} \mathrm{O}_{4}}[\mathrm{~B}]+\mathrm{K}_{2} \mathrm{SO}_{4}
$$
The products $[\mathrm{A}]$ and $[\mathrm{B}]$, respectively are :