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[JEE-Main 2023
08-04-2023_(S2)
Question
If $\alpha>\beta>0$ are the roots of the equation $a x^2+b x+1=0$, and $\lim _{x \rightarrow \frac{1}{\alpha}}\left(\frac{1-\cos \left(x^2+b x+a\right)}{2(1-\alpha x)^2}\right)^{\frac{1}{2}}=\frac{1}{k}\left(\frac{1}{\beta}-\frac{1}{\alpha}\right)$, then k is equal to
Select the correct option:
A
$2 \beta$
B
$2 \alpha$
C
$\alpha$
D
$$ \beta $$
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Solution
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Question Tags
JEE Main
Mathematics
Medium
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