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JEE ADVANCE 2011
paper 2
Question
If $\lim _{x \rightarrow 0}\left[1+x \ln \left(1+b^2\right)\right]^{1 / x}=2 b \sin ^2 \theta, b>0$ and $\theta \in(-\pi, \pi]$, then the value of $\theta$ is
Select the correct option:
A
$\pm \frac{\pi}{4}$
B
$\pm \frac{\pi}{3}$
C
$\pm \frac{\pi}{6}$
D
$\pm \frac{\pi}{2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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