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JEE Main 2020
02-09-2020 S1
Question
If $|x|<1,|y|<1$ and $x \neq y$, then the sum to infinity of the following series $(x+y)+\left(x^2+x y+y^2\right)+\left(x^3\right. \left.+x^2 y+x y^2+y^3\right)+\ldots$. is:
Select the correct option:
A
$\frac{x+y+x y}{(1+x)(1+y)}$
B
$\frac{x+y-x y}{(1-x)(1-y)}$
C
$\frac{x+y-x y}{(1+x)(1+y)}$
D
$\frac{x+y+x y}{(1-x)(1-y)}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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