In a multielectron atom, which of the following orbitals described by three quantum numbers will have same energy in absence of electric and magnetic fields?
A. ${\rm{n}} = 1,{\rm{l}} = 0,\;{{\rm{m}}_1} = 0$
B. ${\rm{n}} = 2,{\rm{l}} = 0,\;{{\rm{m}}_1} = 0$
C. ${\rm{n}} = 2,1 = 1,\;{{\rm{m}}_1} = 1$
D. ${\rm{n}} = 3,{\rm{l}} = 2,\;{{\rm{m}}_1} = 1$
E. ${\rm{n}} = 3,{\rm{l}} = 2,\;{{\rm{m}}_1} = 0$
Choose the correct answer from the options given below: