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JEE MAIN 2026
21-01-2026 S1
Question
Let $a_1=1$ and for $n \geq 1, a_{n+1}=\frac{1}{2} a_n+\frac{n^2-2 n-1}{n^2(n+1)^2}$. Then $\left|\sum_{n=1}^{\infty}\left(a_n-\frac{2}{n^2}\right)\right|$ is equal to
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Mathematics
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