Let the product of the focal distances of the point $\left( {\sqrt 3 ,\frac{1}{2}} \right)$ on the ellipse $\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,(a > b)$, be $\frac{7}{4}$. Then the absolute difference of the eccentricities of two such ellipses is
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