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JEE MAIN 2026
22-02-2026 S1
Question
Net gravitational force at the center of a square is found to be $F_1$ when four particles having mass M , $2 \mathrm{M}, 3 \mathrm{M}$ and 4 M are placed at the four corners of the square as shown in figure and it is $F_2$ when the positions of 3 M and 4 M are interchanged. The ratio $\frac{F_1}{F_2}$ is $\frac{\alpha}{\sqrt{5}}$. The value of $\alpha$ is $\_\_\_\_$ .
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Select the correct option:
A
2
B
3
C
1
D
$2 \sqrt{5}$
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Solution
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Question Tags
JEE Main
Physics
Medium
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