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JEE MAIN 2026
23-01-2026 S1
Question
The equation of the electric field of an electromagnetic wave propagating through free space is given by: $E=\sqrt{377} \sin \left(6.27 \times 10^3 t-2.09 \times 10^{-5} x\right) \mathrm{N} / \mathrm{C}$
The average power of the electromagnetic wave is $\left(\frac{1}{\alpha}\right) \mathrm{W} / \mathrm{m}^2$. The value of $\alpha$ is
$\left(\right.$ Take $\sqrt{\frac{\mu_0}{\varepsilon_0}}=377$ in SI units $)$
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JEE Main
Physics
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