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JEE MAIN_2026_
220126_S1
Question
The number of solutions of $\tan ^{-1} 4 x+\tan ^{-1} 6 x=\frac{\pi}{6}$, where $-\frac{1}{2 \sqrt{6}}<x<\frac{1}{2 \sqrt{6}}$, is equal to
Select the correct option:
A
3
C
1
D
2
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
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