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JEE MAIN 2022
26.07.2022_S2
Question
The oscillating magnetic field in a plane electromagnetic wave is given by $B_y=5 \times 10^{-6} \sin 1000 \pi\left(5 x-4 \times 10^8\right.$ t)T. The amplitude of electric field will be :
Select the correct option:
A
$15 \times 10^2 \mathrm{Vm}^{-1}$
B
$5 \times 10-6 \mathrm{Vm}^{-1}$
C
$16 \times 10^{12} \mathrm{Vm}^{-1}$
D
$4 \times 10^2 \mathrm{Vm}^{-1}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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