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JEE MAIN 2022
28-07-2022 S2
Question
The potential energy of a particle of mass 4 kg in motion along the $x$-axis is given by $U=4(1-\cos 4 x) \mathrm{J}$. The time period of the particle for small oscillation $(\sin \theta=\theta)$ is $\left(\frac{\pi}{K}\right) s$. The value of $K$ is
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Question Tags
JEE Main
Physics
Hard
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