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JEE MAIN 2025
04-04-2025 S2
Question
There are 'n' number of identical electric bulbs, each is designed to draw a power p independently from the mains supply. They are now joined in series across the mains supply. The total power drawn by the combination is :
Select the correct option:
A
$\frac{\mathrm{p}}{\mathrm{n}}$
B
P
C
$\frac{\mathrm{p}}{\mathrm{n}^2}$
D
np
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & R_s=R_1+R_2+R_3+\ldots \ldots \ldots+R_n \\ & \frac{V^2}{P_s}=\frac{V^2}{P}+\frac{V^2}{P}+\ldots \ldots+\frac{V^2}{P_n} \\ & P_s=\frac{P}{n}\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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