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JEE MAIN 2019
12-01-2019 S2
Question
If $A=\left[\begin{array}{ccc}1 & \sin \theta & 1 \\ -\sin \theta & 1 & \sin \theta \\ -1 & -\sin \theta & 1\end{array}\right]$; then for all $\theta \in\left(\frac{3 \pi}{4}, \frac{5 \pi}{4}\right)$, $\operatorname{det}(A)$ lies in the interval :
Select the correct option:
A
$\left(1, \frac{5}{2}\right]$
B
$\left(0, \frac{3}{2}\right]$
C
$\left[\frac{5}{2}, 4\right)$
D
$\left(\frac{3}{2}, 3\right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
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