In a group of 3 girls and 4 boys, there are two boys $B_1$ and $B_2$. The number of ways, in which these girls and boys can stand in a queue such that all the girls stand together, all the boys stand together, but $B_1$ and $B_2$ are not adjacent to each other, is :
Select the correct option:
A
120
B
72
C
144
D
96
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
\begin{aligned}
&\text { Total - when } B_1 \text { and } B_2 \text { are together }\\
&=2!(3!4!)-2!(3!(3!2!))=144
\end{aligned}
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