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JEE MAIN 2022
28-6-2022 S1
Question
Let $y=y(x)$ be the solution of the differential equation $x\left(1-x^2\right) \frac{d y}{d x}+\left(3 x^2 y-y-4 x^3\right)=0, x>1$, with $y(2)=-2$. Then $y(3)$ is equal to
Select the correct option:
A
–18
B
–12
C
–6
D
–3
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Mathematics
Medium
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