Two cells of emf 2E and E with |Current Electricity|JEE-MAIN

JEE-MAIN 2021

17-03-2021 S2

Question

Two cells of emf 2E and E with internal resistance r1 and r2 respectively are connected in series to an external resistor R (see figure). The value of R, at which the potential difference across the terminals of the first cell becomes zero is

Select the correct option:

$r_1+r_2$

$\frac{r_1}{2}-r_2$

$\frac{r_1}{2}+r_2$

$r_1-r_2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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