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QJEE MAIN 2026
In period 4 of the periodic table, the elements with highest and lowest atomic radii are respectively.
JEE MainChemistryEasy
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QJEE MAIN 2026
The correct order of $\mathrm{C}, \mathrm{N}, \mathrm{O}$ and F in terms of second ionisation potential is
JEE MainChemistryEasy
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QJEE MAIN 2026
Given below are two statements: Statement I: $\mathrm{K}>\mathrm{Mg}>\mathrm{Al}>\mathrm{B}$ is the correct order in terms of metallic character. Statement II: Atomic radius is always...
JEE MainChemistryEasy
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QJEE MAIN_2026_
Consider the elements $\mathrm{N}, \mathrm{P}, \mathrm{O}, \mathrm{S}, \mathrm{Cl}$ and F . The number of valence electrons present in the elements with most and least metallic...
JEE MainChemistryEasy
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QJEE MAIN 2026
Given below are two statements: Statement I: The second ionisation enthalpy of Na is larger than the corresponding ionisation enthalpy of $M g$. Statement II:...
JEE MainChemistryEasy
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QJEE MAIN 2026
Elements X and Y belong to Group 15. The difference between the electronegativity values of ' X ' and phosphorus is higher than that of...
JEE MainChemistryMedium
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QJEE MAIN 2026
The correct trend in the first ionization enthalpies of the elements in the $3^{\text {rd }}$ period of periodic table is :
JEE MainChemistryEasy
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QJEE MAIN 2026
Given below are two statements: Statement I: The correct order in terms of atomic/ionic radii is $\mathrm{Al}>\mathrm{Mg}>\mathrm{Mg}^{2+}>\mathrm{Al}^{3+}$. Statement II: The correct order in terms of...
JEE MainChemistryEasy
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QJEE MAIN 2026
Given below are two statements Statement I: $\mathrm{C}<\mathrm{O}<\mathrm{N}<\mathrm{F}$ is the correct order in terms of first ionization enthalpy values. Statement II: $\mathrm{S}>\mathrm{Se}>\mathrm{Te}>\mathrm{Po}>\mathrm{O}$ is the correct...
JEE MainChemistryEasy
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QJEE MAIN_2026_
Which of the following represents the correct trend for the mentioned property? A. $\mathrm{F}>\mathrm{P}>\mathrm{S}>\mathrm{B}$ - First lonization Energy B. $\mathrm{Cl}>\mathrm{F}>\mathrm{S}>\mathrm{P}$ - Electron Affinity C. $\mathrm{K}>\mathrm{Al}>\mathrm{Mg}>\mathrm{B}-$...
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