$1 \times 10^{-5} \mathrm{M} \mathrm{AgNO}_3$ is added to 1 L of saturated solution of AgBr . The conductivity of this solution at 298 K is $\_\_\_\_$ $\times 10^{-8} \mathrm{~S} \mathrm{~m}^{-1}$. [Given: $\mathrm{K}_{\mathrm{sp}}(\mathrm{AqBr})=4.9 \times 10^{-13}$ at 298 K $$ \left.\lambda_{\mathrm{Ag}^{+}}^0=6 \times 10^{-3} \mathrm{~S} \mathrm{~m}^2 \mathrm{~mol}^{-1}, \lambda_{\mathrm{Br}}^0=8 \times 10^{-3} \mathrm{~S} \mathrm{~m}^2 \mathrm{~mol}^{-1}, \lambda_{\mathrm{NO}_3^{-}}^0=7 \times 10^{-3} \mathrm{~S} \mathrm{~m}^2 \mathrm{~mol}^{-1}\right] $$