An inductor of inductance 10 mH having | EMI | JEE MAIN_2026

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JEE MAIN_2026

06-04-26_S1

Question

An inductor of inductance 10 mH having resistance of $100 \Omega$ is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous voltages across the inductor when the current passing through it is 2 mA and 4 mA is $\_\_\_\_$ .

Select the correct option:

A

4/3

B

3/4

C

5/3

D

3/5

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Apply KVL $$ \begin{aligned} & E-i R-V_L=0 \\ & V_L=E-i R=1-100 i \\ & \text { at } i_1=2 \times 10^{-3} \mathrm{~A} \\ & V_{L_1}=0.8 \mathrm{~V} \\ & \text { at } i_2=4 \times 10^{-3} \mathrm{~A} \\ & V_{L_2}=0.6 \mathrm{~V} \\ & \therefore \frac{V_{L_1}}{V_{L_2}}=\frac{4}{3} \end{aligned} $$

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