One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium.
$$
A(g) f \quad B(g)
$$
$\mathrm{K}_{\mathrm{c}}$ for this reaction at 400 K is 4.0 . The partial pressures (in atm) of He and $\mathrm{B}(\mathrm{g})$
are respectively (at equilibrium)
(Assume $\mathrm{He}, \mathrm{A}(\mathrm{g})$ and $\mathrm{B}(\mathrm{g})$ behave as ideal gases)
(Given : $\mathrm{R}=0.082 \mathrm{Latm} \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ )
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