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JEE MAIN 2026
06-04-2026 S2
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Let $f(x)=\left\{\begin{array}{ll}x^3+8 ; & x<0, \\ x^2-4 ; & x \geq 0,\end{array}\right.$ and $g(x)= \begin{cases}(x-8)^{1 / 3} ; & x<0, \\ (x+4)^{1 / 2} ; & x \geq 0 .\end{cases}$ Then the number of points, where the function gof is discontinuous, is $\_\_\_\_$ .
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