Let $a_1=b_1=1$ and $a_n=a_{n-1}+(n-1), b_n=b_{n-1}+a_{n-1}, \forall n \geq 2$. If $\sum_{n=1}^{10} \frac{b_n}{2^n}$ and $T=\sum_{n=1}^8 \frac{n}{2^{n-1}}$, then $2^7(2 S-$ T ) is equal to $\_\_\_\_$ .
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