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JEE MAIN 2023
02-04-2023-S2
Question
Let $T$ and $C$ respectively be the transverse and conjugate axes of the hyperbola $16 x^2-y^2+64 x+4 y+ 44=0$. Then the area of the region above the parabola $x^2=y+4$, below the transverse axis $T$ and on the right of the conjugate axis C is:
Select the correct option:
A
$4 \sqrt{6}+\frac{44}{3}$
B
$4 \sqrt{6}+\frac{28}{3}$
C
$4 \sqrt{6}-\frac{44}{3}$
D
$4 \sqrt{6}-\frac{28}{3}$
✓ Correct! Well done.
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